Mathematical Literacy: 2016

12/15/2016

12/05/2016 Section 3: Methods of determining possible outcomes

12/05/2016 Afdeling 3: Metodes om moontlike uitkomste te bepaal.

Two-way tables

Tweerigting-tabelle

*You need to be able to read (calculate possible outcomes) and draw the two-way table.

*Jy gaan moet kan lees (bereken die waarskynlikheid/moontlike uitkomste) en ook die tweerigting-tabel kan teken.

Let’s calculate the following probabilities (P):

1) P(women preferred drama) = 13/90 (as % only x 100 = 14,4%)

2) P(men preferred crime) = 22/90 (x 100 = 24,4%)

11/05/2016

11/05/2016 Section 3: Methods of determining possible outcomes

11/05/2016 Afdeling 3: Metodes om moontlike uitkomste te bepaal.

Tree diagrams

Boomdiagramme

The HE, SHE, FLIP A COIN game

Die HY, SY, SKIET ‘n MUNTSTUK spelletjie

- 1^stgirls flip a coin. - 1^st skiet die meisie die muntstuk

- 2^nd boys flip a coin. - 2^de skiet die seuns die muntstuk

Conditions:

Voorwaardes:

- If both of the coins landed on HEADS [female give the male 3 points/sweets]

As beide op KOP land [meisies gee die seuns 3 punte].

- If both of the coins landed on TAILS [female give the male 1 point/sweet]

As beide op STERT land [meisies gee die seunrs 1 punt].

- If the boy’s coin not the same as the girl’s coin [male give the female 2 points/sweets]

As die seuns se muntstuk nie dieselfde is as die meisies sin nie [seuns gee meisies 2 punte].

Let’s put the possible outcomes on a tree diagram.

Determine the possible outcomes using the tree diagram:

1) What is the probability that both coins will land on heads?

P(Both heads) = 1/4

2) What is the probability that one coin will land on heads and the other on tails?

P(One land on tails) = 2/4

3) P(Both tails) = 1/4

4) P(1^st H; 2^nd T) = 1/4

5) P(1^st T; 2^nd H) = 1/4

Bereken die moontlike uitkomste deur die boomdiagram te gebruik:

1) Wat is die moontlikheid dat beide muntstukke op Kop sal land?

W(Beide Kop) = 1/4

2) Wat is die waarskynlikheid dat die een muntstuk op Kop sal land en die ander op stert?

W(Een Kop en ander Stert) = 2/*4

3) W(Beide Stert) = 1/4

4) W(1^st K; 2^de S) = 1/4

5) W(1^st S; 2^de K) =

Exercise 3 nr. 1 – 4 p. 146

Oefening 3 nr 1 – 4 bl. 146

Exercise 4 p. 146 [Oefening 4 bl. 146]

Exercise 4 p. 146

Oefening 4 bl. 146

1. 1.1)

	In favour	Opposed	Undecided	Total
Men	212	87	25	324
Women	52	30	77	159
Total	264	117	102	483

	In Gunste van	Daar teen	Nog nie besluit nie	Totaal
Mans	212	87	25	324
Vroue/Dames	52	30	77	159
Totaal	264	117	102	483

1.2)

	In favour	Opposed	Undecided	Total
Men	= 43,9%	= 18%	= 5,2%	= 67,1%
Women	=10,8%	= 6,2%	= 15,9%	= 32,9%
Total	= 54,7%	= 24,2%	= 21,1%	= 100%

	In Gunste van	Daar teen	Nog nie besluit nie	Totaal
Mans	= 43,9%	= 18%	= 5,2%	= 67,1%
Dames/Vroue	=10,8%	= 6,2%	= 15,9%	= 32,9%
Totaal	= 54,7%	= 24,2%	= 21,1%	= 100%

1.3.1) P(men in favour) = 43,9% W(mans in gunste van) = 43,9%

1.3.2) P(women undecided) = 15,9% W(Dames nog nie besluit nie) = 15,9%

1.4) Yes, there is more than 50% that are in favour of the supermarket. Therefore there is more than half of the person already agreed to the supermarket. There is 21,1% of people undecided that may change their mind later and be in favour of the supermarket.

Ja, daar is meer as 50% van die mense ten gunste van die supermark. Daar is meer as die helfte van die mense wat reeds belangstel aan die supermark. Daar is 21,1% van die mense wat nog nie besluit het nie en kan dalk later ten gunste van die supermar wees.

2. 2.1)

Grade	Weight status
	Underweight	Average weight	Overweight	Total
8	0	1	1	2
9	1	2	1	4
10	0	4	1	5
11	2	1	4	7
12	0	4	2	6
Total	3	12	9	24

Graad	Gewig status
	Ondergewig	Gemiddelde gewig	Oorgewig	Totaal
8	0	1	1	2
9	1	2	1	4
10	0	4	1	5
11	2	1	4	7
12	0	4	2	6
Totaal	3	12	9	24

2.2.1) 24

2.2.2) 9

2.2.3) 1

2.3.1) P(Grade 8 underweight) = 0/24 = 0%

W(Graad 8 ondergewig) = 0/24 = 0%

2.3.2) P(Grade 12 average weight) = 4/24 = 16,7%

W(Graad 12 gemiddelde gewig) = 4/24 = 16,7%

Monday, 16 May 2016

12/15/2016

11/05/2016

Exercise 4 p. 146 [Oefening 4 bl. 146]